The Raiders reach a deal with TE Austin Hooper

Paul GutierrezESPN staff writer2 minutes to read

HENDERSON, Nevada — After they traded former Pro Bowler starting free agency starter Darren Waller, the Las Vegas Raiders on Wednesday reached a free agent agreement with another former Pro Bowler in Austin Hooper.

Terms were not disclosed by the Raiders, but a source confirmed to ESPN that Hooper, who spent last season with the Tennessee Titans, has agreed to a one-year deal.

He is joined by OJ Howard, who signed with the Raiders on Monday, and returning players Jesper Horsted and Cole Fotheringham. The Raiders traded Waller, who set a franchise record with 107 catches in 2020, to the New York Giants for a third-round pick in this spring draft, his 100th overall, earlier this month.

Hooper was released by the Cleveland Browns last year, and he signed a one-year, $6 million deal with the Titans before the 2022 season. He started slow but posted 24 of 41 receptions over the last eight games. Hooper received two touchdowns, tying him with Robert Woods for third on the team.

Hooper, 28, has only started two games for the Titans, but his 503 snaps are second among the team’s tight ends. He was used primarily as a passing option for Tennessee.

Hooper, a two-time Pro Bowl selection, was originally selected by the Atlanta Falcons in the third round from Stanford in the 2016 draft and spent his first four seasons with the team. The Browns signed Hooper to a four-year, $44 million contract in 2020.

He has 339 catches for 3,468 yards and 25 touchdowns in his career.

ESPN’s Toron Davenport contributed to this report.

Leave a Reply

Your email address will not be published. Required fields are marked *